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7x^2+14x-336=0
a = 7; b = 14; c = -336;
Δ = b2-4ac
Δ = 142-4·7·(-336)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9604}=98$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-98}{2*7}=\frac{-112}{14} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+98}{2*7}=\frac{84}{14} =6 $
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